$
$ TEST INPUT DECK FOR SUPERELEMENT BOUNDARY LOADS ALTER PACKAGE
$             (sebload1.dat)
$
$ PROCEDURE DESCRIBED IN 1992 WORLD USER'S CONFERENCE PAPER BY
$ JIM SWAN OF THE MSC.Software CORPORATION
$
$
$ TEST CASE IS A SIMPLE ZERO-DENSITY CANTILEVERED BEAM WITH A LARGE BASE
$ MASS (USED TO IMPART BASE LATERAL MOTION) AND A SMALLER WEIGHT AT
$ THE TIP OF THE BEAM.  THE BEAM IS MADE UP OF 5 BEAM ELEMENTS AND
$ IS BROKEN UP INTO ONE UPSTREAM SUPERELEMENT AND THE RESIDUAL.  THE
$ UPSTREAM SUPERELEMENT ARE THE LAST 2 ELEMENTS AT THE FREE END OF
$ THE BEAM.  ELEMENT FORCES AT END B OF BEAM 34 (LAST ELEMENT IN THE
$ RESIDUAL) CAN BE COMPARED TO THE SUPERELEMENT BOUNDARY FORCES
$ CALCULATED BY THE DMAP ALTER (NOTE: ELEMENT FORCES LAG THE SE
$ BOUNDARY FORCES SLIGHTLY IN THIS EXAMPLE, BUT THE MAGNITUDES OF
$ THE TWO LOADS TRACK VERY WELL).  THE DECK IS NOMINALLY SETUP FOR
$ A MODAL TRANSIENT RUN/SOL 112, BUT CARDS FOR A FREQUENCY RESPONSE
$ ANALYSIS ARE INCLUDED.  THIS PROBLEM CAN BE RUN EITHER USING A
$ MODAL OR DIRECT APPROACH.
$
$.......2.......3.......4.......5.......6.......7.......8.......9.......0
INIT MASTER(S)  $ SCRATCH RUN
$ ID MSC, SWRO
ID MSC, SEBLOAD1
TIME 10
SOL 112                   $ ANY SOLUTION 108, 109, 111, 112
INCLUDE 'sebloada.v2001' $ SUPERELEMENT BOUNDARY LOADS ALTER PACKAGE
diag 8
CEND
$
TITLE = ZERO-DENSITY CANTILEVERED BEAM WITH TIP MASS           SEBLOAD1
$
SUBCASE    100            $ UPSTREAM
  LABEL  = UPSTREAM SUPERELEMENT 100
  SUPER  = 100
$ METHOD = 100            $ UPSTREAM CMS (OPTIONAL)
  PARAM, SEBFORCE, 1      $ ACTIVATE SE BOUNDARY FORCE CALCULATIONS
  PARAM, GRDPNT,   4      $ RESULTANT LOADS ABOUT GRID 4
  SET 4  =   4            $ BOUNDARY GRIDS/SPOINTS SET
  OLOAD(PRINT,PUNCH) = 4  $ UPSTREAM OLOAD FOR SE BOUNDARY FORCES
$
SUBCASE    999            $ RESIDUAL
  LABEL  = RESIDUAL STRUCTURE
  METHOD = 100            $ SYSTEM MODES
  SDAMP  = 200            $ RESIDUAL STRUCTURE MODAL DAMPING
  DLOAD  = 300            $ TRANSIENT RESPONSE DYNAMIC LOADS
  TSTEP  = 400            $ TRANSIENT RESPONSE TIME STEPS
$ DLOAD  = 500            $ FREQUENCY RESPONSE DYNAMIC LOADS
$ FREQ   = 600            $ FREQUENCY RESPONSE OUTPUT FREQUENCIES
  SET 34 =  34            $ ELEM 34 IS LAST ELEM IN RESIDUAL
  FORCE(PRINT,PUNCH) = 34 $ COMPARE FORCE VS SE BOUNDARY FORCE
BEGIN BULK
$.......2.......3.......4.......5.......6.......7.......8.......9.......0
$
$ BULK DATA SECTION FOR ZERO-DENSITY CANTILEVERED BEAM WITH TIP MASS
$    *** INBOARD (RESIDUAL) SECTION ***
$
$.......ID......CP......X1......X2......X3......CD......PS......SEID....1
GRID    1                0.     0.      0.              13456   0
GRID    2                2.     0.      0.              1345    0
GRID    3                4.     0.      0.              1345    0
GRID    4                6.     0.      0.              1345    0
$
$.......EID.....PID.....GA......GB......X1......X2......X3......
CBAR    12      1       1       2       0.      -1.     0.
CBAR    23      1       2       3       0.      -1.     0.
CBAR    34      1       3       4       0.      -1.     0.
$
$.......PID.....MID.....A.......I1......I2......J.......NSM.....
PBAR    1       1               2.E-3
$
$.......MID.....E.......G.......NU......RHO.....
MAT1    1       10.E6           .3      0.
$
$.......EID.....G.......CID.....M.......
CONM2   101     1               1.E+3
$
$.......2.......3.......4.......5.......6.......7.......8.......9.......0
$
$
$
$ ZERO-DENSITY CANTILEVERED BEAM MODEL WITH TIP MASS
$ *** OUTBOARD (UPSTREAM SE)  SECTION ONLY ***
$
$.......ID......CP......X1......X2......X3......CD......PS......SEID....1
GRID    5                8.     0.      0.              1345    100
GRID    6               10.     0.      0.              1345    100
$
$.......EID.....PID.....GA......GB......X1......X2......X3......
CBAR    45      2       4       5       0.      -1.     0.
CBAR    56      2       5       6       0.      -1.     0.
$
$.......PID.....MID.....A.......I1......I2......J.......NSM.....
PBAR    2       2               2.E-3
$
$.......MID.....E.......G.......NU......RHO.....
MAT1    2       10.E6           .3      0.
$
$.......EID.....G.......CID.....M.......
CONM2   106     6               1.E-2
$
$
$.......2.......3.......4.......5.......6.......7.......8.......9.......1
$
$ ZERO-DENSITY CANTILEVERED BEAM MODEL WITH TIP MASS
$ DYNAMICS RELATED CARDS
$
$ MODAL INFORMATION:
$.......SID.....V1......V2......ND......MSGLVL..MAXSET..SHFSCL..
EIGRL   100                     3
$
$.......2.......3.......4.......5.......6.......7.......8.......9.......1
PARAM   G       0.2
PARAM   W3      77.5
$
$.......TID.....TYPE....
$.......X1......Y1......X2......Y2......X3......Y3......X4......Y4......
TABDMP1 200     CRIT
        0.      0.08    1000.   0.08    ENDT
$ ---------------------------------------------------------------------
$
$
$ TRANSIENT RESPONSE INFORMATION:
$ FULL 12.5 HZ SINE WAVE (ONLY) LOAD STARTING A 0.015 SEC
$ APPLIED TO BASE POINT
$
$.......SID.....DAREA...DELAY...TYPE....T1......T2......F.......THETA
TLOAD2  300     301             0       0.015   0.095   12.5    -90.
$
$.......ID......G.......C.......A.......
DAREA   301     1       2       1.E+6
$
$.......SID.....NT......DT......NO......
TSTEP   400     69      .005    1
$
$ ---------------------------------------------------------------------
$
$
$ FREQUENCY RESPONSE INFORMATION:
$.......SID.....DAREA...DELAY...DPHASE..TC......TD......
RLOAD1  500     501                     502
$
$.......ID......G.......C.......A.......
DAREA   501     1       2       1.E+6
$
$.......ID......
$.......X1......Y1......X2......Y2......X3......Y3......X4......Y4......
TABLED1 502
        0.      0.      1.      1.      20.     1.      21.     0.
        10000.  0.      ENDT
$
$.......SID.....F1......DF......NDF.....
FREQ1   600     1.      1.      19
FREQ1   600     10.5    1.      4
FREQ1   600     12.1    .1      9
$.......2.......3.......4.......5.......6.......7.......8.......9.......1
$
ENDDATA