1) From the Main Toolbox, right-click the Rigid Body tool stack, and then select the Rigid Body: Box tool.
2) Create a Rigid Body:Box by clicking on the grid. The dimension of the box is not important, so just create any type of box.
3) Right-Click on the Box and choose Part:PART_2 : Modify. Input the Mass as 187.224.
4) After inputing the Mass, click OK.
1) First right-click on the screen and choose Rotate XY then rotate the model until it is similar to the view below. It is best to check the translational joint that will be created by rotating the model to make sure that it is fix in the yg direction.
2)Now click on Joint: Translational.
3) Choose the Rigid Body : Box, when it says "Select the first body" on the bottom of the screen.
4) Choose the Ground, when it says "Select the second body" on the bottom of the screen.
5) Choose the PART_2.cm, when it says "Select the location" on the bottom of the screen.
6) Choose the cm.X, when it says "Select the dirction vector" on the bottom of the screen.
7) To verify the expected behavior, simulate the model by clicking on the Interactive Simulation Controls.
8) Click on the Play icon to run the simulation and click on the Reset icon.
1) Click on the Translational spring damper.
2) Input the K value of 5 and the C value of 0.05.
3) Choose the PART_2.cm, when it says "Select the first point" on the bottom of the screen.
4) Right-click anywhere on the ground to display the Location Event. Enter 0, 400, 0, and change Rel. to Origin to Rel. to Grid.
5) Click Apply.
1) Click on Tools and choose Measure Distance....
2) Click on First Position and choose cm, because this is the position where one of the spring end is located.
3) Click on Second Position and choose MARKER_5, because this is the position where the other spring end is located. Then click OK.
4) Verify the value of Y.
1) Select Interactive Simulation Controls on the Main Toolbox.
2) Select the Static Equilibrium tool.
3) Select Force Graphics... under Settings on the Main Menu.
4) Put a check on Display Numeric Values on the Force Graphics Settings.
5) Click OK. Zoom out until you can see the force value. As shown the force in the spring damper at static equilibrium is 1836.04 N.
- The block’s mass is 187.224 kg.
- Therefore, to balance the force of gravity, the spring damper must generate:
- The results produced by Adams View is the same as the hand calcuated answer.
- 187.224 kg * 9806.65 mm/s2 = 1836.04 N